Question

2y cosA= x sinA And 2x secA - y cosecA = 3 find the relation between x and y

Answer 1

2y cosA= xsinA
     cosA=xsinA/2y

since, cosA=1/secA
therefore, secA= 1/cosA
                            2y/xsinA

now put the value of secA in second equation
2x(2y/xsinA) - ycosecA=3
4y/sinA - y/sinA=3                               since cosecA=1/sinA
3y/sinA  = 3
y= sinA.
from equation 1, x= 2sinAcosA/sinA
                           x= 2cosA