2y+ix=4+x-i find x and y
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Answer:
Given, 2y+ix=4+x−i
First equating real terms, we get
2y=4+x
And now equating imaginary terms,
x=−1
Putting this value of x in equation (1), we get
2y=4+x
=> 2y=4−1
=> 2y=3
=> y = 3/2
Therefore, x=−1, and y=3/2
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