Question

2y square+27y+13=0.Solve the quadratic equation by factorisation.

Answer 1

Answer:

Step-by-step explanation:

2Y square + 26y + 1y + 13=0

2¥( ¥ + 13 ) + 1 ( ¥ + 13) =0

(¥+13) (2¥ + 1) = 0

¥=-13 or -1

Answer 2

${2y}^{2} + 27y + 13 = 0 \\ \\ write \: 27y \: as \: a \: sum \\ \\ 2 {y}^{2} + 26y + y + 13 = 0 \\ \\ factor \: out \: 2y \: from \: the \: expression \\ \\ 2y(y + 13) + y + 13 = 0 \\ \\ factor \: out \: y + 13 \: \\ \\ (y + 13)(2y + 1) = 0$

$y + 13 = 0 \times( 2y + 1) \\ \\ y + 13 = 0 \\ \\ if \: we \: take \: 2y + 1 \: then \\ \\ 2y + 1 = 0 \times (y + 13) \\ \\ 2y + 1 = 0 \\ \\ therefore \\ \\ \binom{y + 13 = 0}{2y + 1 = 0} \\ \\ \binom{y = 0 - 13}{2y = - 1} \\ \\ \binom{y = - 3}{y = - \frac{1}{2} } \\ \\ \binom{y = - 13}{y = - 0.5}$

$therefore \\ \\ y1 = - 13\: \: and\: \: y2 = - \frac{1}{2}\: \: or \: \: - 0.5$