Question

2y square- (2y+3)(y-1)/3y-5=-1/2

Answer 1

Answer:

12y^3-24y^2+y+1=0

Step-by-step explanation:

2y^2-(2y+3)(y-1)/3y-5=-1/2

by doing LCM on left hand side for subtraction

2y^2(3y-5)-(2y^2+3y-2y-3)

--------------–----–------――-----=-1/2

3y-5

6y^3-10y^2-2y^2-3y+2y+3=-1/2×(3y-5)

2(6y^3-12y^2-y+3)=-(3y-5)

12y^3-24y^2-2y+6=-3y+5

12y^3-24y^2-2y+6+3y-5=0

12y^3-24y^2+y+1=0