2y-x=0; 10x+15y=105, Solve the set of simultaneous equations.
Answers
Answered by
43
10x + 15y = 105 ------(1)
2y - x = 0
=> x = 2y
On substituting the value of x in equation 1, we get
10(2y) + 15y = 105
=> 20y + 15y = 105
=> 35y = 105
=> y = 3
x = 2 × 3 = 6
2y - x = 0
=> x = 2y
On substituting the value of x in equation 1, we get
10(2y) + 15y = 105
=> 20y + 15y = 105
=> 35y = 105
=> y = 3
x = 2 × 3 = 6
Answered by
39
Hey Mate !!
Given,
The above equations can be solved through the Substitution method.
10x + 15y = 105 ----(1)
2y - x = 0
x = 2y
Substitute x in eq - 1
10 (2y) + 15y = 105
20y + 15y = 105
35y = 105
y = 105/35
y = 3
Substitute y in eq 2
2 (3) - x = 0
6 - x = 0
x =6
Given,
The above equations can be solved through the Substitution method.
10x + 15y = 105 ----(1)
2y - x = 0
x = 2y
Substitute x in eq - 1
10 (2y) + 15y = 105
20y + 15y = 105
35y = 105
y = 105/35
y = 3
Substitute y in eq 2
2 (3) - x = 0
6 - x = 0
x =6
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