Question

2y/y-4 + 2y-5/y-3 = 25/3

Answer 1

(2y - 4y) / y +(2y - 5) / y-3 = 25 /3

-2y/y +2y-5 /y-3= 25/3

6y + 2y - 5 / y-3 =25 /3

8y-5/y-3 =25/3

24y-15=25y-75

25y -24 y=75 -15

.°.y =60

Answer 2

$\frac{2y}{y-4}+ \frac{2y-5}{y-3} = \frac{25}{3}$

$\frac{2y(y-3)}{y-4(y-3)}+ \frac{2y-5(y-4)}{y-3(y-4)} = \frac{25}{3}$

$\frac{2y(y-3)+2y-5(y-4)}{y-4(y-3)}} = \frac{25}{3}$

$\frac{2y^{2}-6y+2y^{2}-8y -5y+20)}{y^{2} -3y-4y+12}} = \frac{25}{3}$

$\frac{4y^{2}-19y +20}{y^{2} -7y+12}} = \frac{25}{3}$

$12y^{2} -57y+60 = 25y^{2} -175 y+300$

$13y^{2} -118y+240$

y = 6 and y = 3.0697....