Question

2y(-y²+3y-4)
Solve this algebraic expression
pls do not google
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Answer 1

Answer:

2y(-y²+3y-4)=0

-y²+3y-4=0

y²-3y+4=0

y²+y-4y+4=0

-y(y-1)-4(y-1)=0

(-y-4)(y-1)=0

y=1,4

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✅I hope it is helpful.✅