Question

2y2 + 27y + 13 = 0 by completing square method​

Answer 1

Answer:

2y2 + 27y + 13 = 0

2y2 + 26y + y + 13 = 0

2y(y +13) + 1(y +13) = 0

= (2y + 1)(y + 13)

either, (2y + 1) = 0

2y = -1

y = -1/2

or,

(y +13) = 0

y = -13

Answer 2

Answer:

y=-1/2 or-13

Step-by-step explanation:

2y²+27y+13=0

2y²+26y+y+13=0

2y(y+13)+(y+13)=0

(2y+1)(y+13)=0

2y+1=0 or y+13=0

y=-1/2 or y=-13

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