Question

2y² - 2x + 4y + 1 = 0 ----eq. 1
2(x + 2) (y + 2) = 0 -----eq.2
How was the eq.1 simplified to eq.2? Please explain in detail, I'm stuck in this simplification.​

Answer 1

from eq2 ,

2(xy + 2x + 2y + 4) = 2xy + 4x + 4y + 8

again , by simplifying

2x(y+2) + 4(y+2)

so , taking (y+2) as common

(y+2)(2x+4)