Question

2y2-2y +1 के लिए P(0), P(1) और P(2) ज्ञात कीजिए।​

Answer 1

p(0) = 1 , p(1)=1 , p(2)=5

Step-by-step explanation:

${2y}^{2} - 2y + 1$

1) P(0)=

${2(0)}^{2} - 2(0) + 1$

$= 1$

2) P(1)=

$2 {(1)}^{2} - 2(1) + 1$

$2 - 2 + 1$

$= 1$

3) P(2)=

$2 {(2})^{2} - 2(2) + 1$

$2(4) - 4 + 1$

$8 - 4 + 1$

$= 5$

Hope it helps you!!

:)