Question

2y2 + 3y + 1 = 0..find ​

Answer 1

Answer:

2y^2+2y+y+1

2y(y+1)+1(y+1)

(y+1)(2y+1)

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Answer 2

Answer:

2y2+3y+1=0

2y2+2y+y+1=0

2y(y+1)+1(y+1)=0

(2y+1) (y+1)=0

so the y is

2y+1=0

2y=-1

y=-1/2

or

y+1=0

y=-1