Question

2y2 +3y +1 =how to solve this question

Answer 1

Answer:

2y^2 +3y+1=0

2y^2 + 2y + y + 1 = 0

2y(y+1) + 1(y+1) = 0

(y+1)(2y+1)=0

y= -1. and y = -1/2