2y²-50 Factorise...........
Answers
Answered by
10
Hey there!
2y² - 50
= 2(y² - 25)
= 2(y² - 5²)
= 2(y + 5)(y - 5)
Hope it helps you!
2y² - 50
= 2(y² - 25)
= 2(y² - 5²)
= 2(y + 5)(y - 5)
Hope it helps you!
Answered by
6
2y^2-50
=2(y^2-25)
=2(y^2-5^2)
=2(y+5)(y-5)
Here we used the identity
x^2-y^2=(x+y)(x-y)
=2(y^2-25)
=2(y^2-5^2)
=2(y+5)(y-5)
Here we used the identity
x^2-y^2=(x+y)(x-y)
mysticd:
thank you selecting as brainliest
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