Question

2y² + 8y - 10 = 0, factoring​

Answer 1

Answer:

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$2 {y}^{2} + 8y - 10 = 0 \\ = > 2 {y}^{2} + 10y - 2y - 10 = 0 \\ = > 2y(y + 5) - 2(y+ 5) = 0 \\ = > (y + 5)(2y - 2) = 0$

Answer 2

Answer:

-5 or +1

Step-by-step explanation:

2y² + 8y - 10 = 0, factoring

BY SPLITTING THE MIDDLE TERMS

We need such a number that it's addition is 8 and multiplication is 20 i.e. 2 and 10

2y² -2y+10y-10=0

2y(y-1) +10(y-1) =0

(2y+10)(y-1) =0

y= -5 or +1

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