Question

2y²+8y+16-400=0 Now solve this...go go go...

Answer 1

2y² + 8y + 16 - 400 = 0
2y² + 8y - 384 = 0
Taking 2 as common
y² + 4y - 192 = 0
y² + 16y - 12y - 192 = 0
y (y + 16) - 12(y + 16) = 0
(y + 16) (y - 12) = 0
y = - 16 or y = 12

The value of y is - 16 or 12.

Hope this helps you.

Answer 2

hola!

Given eqn. :
2y² + 8y + 16 - 400 = 0 or 2y² + 8y -384 = 0

Simplifying : y² + 4y - 192 = 0

Discriminant = b² - 4ac

= 4² - 4(1)(-192)

= 16 + 768

= 784 --- [ roots are real n' distinct. D > 0 ]

by Quadratic formula :-

x = -b ± √D/ 2a

x = -4 ± √784/ 2 × 1

x = -4 ± 28/ 2

→ For (-) :-
x = -4 - 28/ 2 = -32/2 = -16

→ For (+)
x = -4 + 28/ 2 = 24/2 = 12

Hence,
The required answer is x = -16 or x = 12.

hope it helps! :)