Question

2y2 + 9y + 10 = 0
$by square method$
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Answer 1

Answer:

4y+ 9y+10=0

13y= 10

y= 10/13

Answer 2

Answer:

$by \: square \: \: method$

$2 {y}^{2} + 9y + 10 = 0$

Answer:

- 2  OR  - 5 / 2

Step-by-step explanation:

Given :

p ( y ) = 2 y² + 9 y +  10 = 0

Dividing by coefficient of y² :

⇒ 2 / 2 y² + 9 / 2 y + 10 / 2 = 0 / 2

⇒ y² + 9 / 2 y + 5 = 0

Now transfer 5 [ constant term ] R.H.S. side :

⇒ y² + 9 / 2 y = -  5

Now Adding ( 1 / 2 × coefficient of y )²

i.e. ( 9 / 4 )² = 81 / 16

⇒ y² + 9 / 2 y + 81 / 16 = 81 / 16 -  5

⇒ y² + 2 . 9 / 4 y + ( 9 / 4 )² = 1 / 16

⇒ ( y + 9 / 4 )² = ( 1 / 16 )

⇒ ( y + 9 / 4 ) = ± ( 1 / 4 )

Value of y as :

y + 9 / 4 = 1 / 4

y = 1 / 4 - 9 / 4

y = - 8 / 4

y = - 2

OR

y + 9 / 4 = - 1 / 4

y = - 9 / 4 - 1 / 4

y = - 10 / 4

y = - 5 / 2 .

Therefore , the value of y is ' - 2 '  OR  ' - 5 / 2 ' .