2y²-y+2=0 please solve
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Hey!
Here is your answer!
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QUADRATIC EQUATION :
2y²-y+2=0
Comparing it with ax²+bx+c=0
We get,
a=2, b= -1 and c=2
Now, we know that
\begin{gathered}discriminant \: (d) = {b}^{2} - 4ac \\ \\ d = { (- 1)}^{2} - 4 \times 2 \times 2 \\ \\ d = 1 - 16 \\ \\ d = - 15\end{gathered}
discriminant(d)=b
2
−4ac
d=(−1)
2
−4×2×2
d=1−16
d=−15
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So the discriminant of this equation is -15.
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Hope it's satisfactory!!!
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