Question

(2y3 + 3y2 - 4y - 5) (y + 1)

Answer 1

2y^4+3y^3-4y^2-5y+2y^3+3y^2-4y-5
= 2y^4+5y^3-y^2-9y-5

Answer 2

(2y^3+3y^2-4y-5)(y+1)
= 2y^4+3y^3-4y^2-5y+2y^3+3y^2-4y-5
= 2y^4 + (3y^3+2y^3)+ (-4y^2+3y^2)+(-5y-4y)-5
= 2y^2+ 5y^3-y^2-9y-5 ans