(2y3+4y2+3)÷2y
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Answer:
= (2y3+4y2+3)/2y
= 2y power 2 (y+2) + 3/2y power 2
= 2y power 2 (y+2)/2y power 2 + 3y/2y power 2
= (y + 2) + 3/2y power 2
Step-by-step explanation:
So, quotient is (y+2) and remainder is 3
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