Math, asked by Srsuhti, 5 months ago

(2y3+4y2+3)÷2y
Please Give Answer​

Answers

Answered by Soumyadaggubati
0

Answer:

= (2y3+4y2+3)/2y

= 2y power 2 (y+2) + 3/2y power 2

= 2y power 2 (y+2)/2y power 2 + 3y/2y power 2

= (y + 2) + 3/2y power 2

Step-by-step explanation:

So, quotient is (y+2) and remainder is 3

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