Question

(2y³÷4y³÷3) ÷2y² plz divislde and write quotient and remainder​

Answer 1

Answer:

Reminder = 0

Quotient → 2y² + 2y + 1 ( a quadratic equation )

To Find :-

→ Quotient and reminder .

Explanation :-

We have ;-

\begin{gathered} \begin{array}{rccccl} y + 1 \bigg) & 2y^3 & + 4y^2 & + 3y & + 1 & \bigg( 2y^2+2y+1 \\ & 2y^3 & 2y^2 &&& \\ \cline{2-5}& & 2y^2 & + 3y & + 1 & \\ & & 2y^2 & + 2y & & \\ \cline{3-5} & & & y & + 1 & \\ & & & y & + 1 & \\ \cline{4-5} & & & & 0\end{array} \end{gathered}

y+1)

\cline2−5

\cline3−5

\cline4−5

2y

3

2y

3

+4y

2

2y

2

2y

2

2y

2

+3y

+3y

+2y

y

y

+1

+1

+1

+1

0

(2y

2

+2y+1

Reminder = 0

Quotient → 2y² + 2y + 1 ( a quadratic equation )

We can solve this quadratic by Shridharacharya principal .

→ If given quadratic is →ax² + bx + c = 0

\sf{ \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }

2a

−b±

b

2

−4ac