Question

2y³+y²-2y-1 by using trial and error method​

Answer 1

Answer:

Given that,

An expression 2y3 + y? – 2y - 1

To find,

Factors of the above expression.

Solution,

We have,

2y3 + y²– 2y - 1

Taking y² common from first two terms and -1 common from last two terms

= y²(2y+ 1) - 1(2y + 1)

= (y² - 1)(2y + 1)

Now using identity, (a² b²) = (a - b)(a + b)

So,

= (2y³ 1)(2y² + 1)(y + 1)

So, the factors of 2y + y² - 2y - 1 is (y - 1)(2y + 1)(y + 1).

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Answer 2

Answer:

.in a rectangular park....

length=21/4 m

perimeter=35/2

=2(l+b)

=2(21/4 ×b)

=21/2 ×b/2

= 35/2 =21/2 ×b/2

=35=21×b

=b=35/21

area=l×b

=21/4 × 35/21

area=35/4