Question

2y3+y2-2y-1 factorise it.

Answer 1

Answer:

2y³+y²-2y-1=(2y+1)(y+1)(y-1)

Step-by-step explanation:

Factorising 2y³+y²-2y-1

= y²(2y+1)-1(2y+1)

= (2y+1)(y²-1)

= (2y+1)(y²-1²)

= (2y+1)(y+1)(y-1)

/* By algebraic identity:

a²-b² = (a+b)(a-b) */

Therefore,

2y³+y²-2y-1=(2y+1)(y+1)(y-1)

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Answer 2

Answer:

$(y-1)(y+1)(2y+1)$

Step-by-step explanation:

Given :$2y^3+y^2-2y-1$

To Find : Factorize

Solution:

$2y^3+y^2-2y-1$

$2y^3-2y+y^2-1$

$2y(y^2-1)+y^2-1$

$(y^2-1)(2y+1)$

Identity : $a^2-b^2=(a+b)(a-b)$

$(y-1)(y+1)(2y+1)$

Hence $2y^3+y^2-2y-1$ is $(y-1)(y+1)(2y+1)$