Question

2y³ + y² - 2y - 1 ÷ (y+1)​

Answer 1

Answer:

Step-by-step explanation:

6y

Answer 2

Answer:

Given :-

➪ 2y³ + y² - 2y - 1 ÷ (y + 1)

Solution :-

➪ 2y³ + y² - 2y - 1 ÷ (y + 1)

➭ 2y³ + y² - 2y - 1/(y + 1)

➭ y²(2y + 1) - 1(2y + 1)/(y + 1)

➭ (2y + 1) (y² - 1)/(y + 1)

➭ (2y + 1) {(y)² - (1)²}/(y + 1)

➭ (2y + 1) (y + 1) (y - 1)/(y + 1)

After cancellation, we get

➻ (2y + 1) (y - 1)

∴ The value of 2y³ + y² - 2y - 1 ÷ (y + 1) is (2y + 1) (y - 1)