Question

2y³× (-y²)× 3xy find the product​

Answer 1

Answer:

Multiplying term by term and then adding,

(2x2−3xy+y2)×(2y2−xy−x2)

=2x2(2y2−xy−x2)−3xy(2y2−xy−x2)+y2(2y2−xy−x2)

=4x2y2−2x3y−2x4−6xy3+3x2y2+3x3y+2y4−xy3−x2y2

=6x2y2−x3y−7xy3+2y4−2x4