2z^2-3z+12=0 Degree1 or degree2
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8x − y +3z =23 We will eliminatextwice. 4x −3y +2z =−29 Start with first two equations.LCM of4and6is 12. 6x+2y −z =−16 Make the first equation have 12x,the second−12x. 3(4x −3y +2z)=(−29)3. Multiply the first ...
Missing: Degree1 degree2
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→ 2z² - 3z + 12 = 0
Degree is the highest power on the given equation. Which is 2
Hence, degree is 2
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