Math, asked by gaminganish432, 18 days ago

(2z-7)-3 (3z+8=4z-9)​

Answers

Answered by AllFatherOdin
1

Answer:

answer is 4z²

Step-by-step explanation:

Answered by ashaingle1983
0

Answer:

Hey there!

Solution:

\begin{gathered}(2z - 7 ) - 3 ( 3z + 8 ) = 4z - 9\\ \\ ( 2z - 7 ) - ( 9z + 24 ) = 4z - 9 \\ \\ ( 2z - 7 ) - 9z - 24 = 4z - 9\\ \\ 2z - 7 - 9z - 24 = 4z - 9\\ \\ 2z - 9z - 4z = -9 + 7 + 24\\ \\ 2z - 9z - 4z = - 2 + 24\\ \\ -11z = 22\\ \\ z = \frac{22}{11}\\ \\ z = - 2 \\ \\ \textbf{To check this}\\ \\ Put z = -2\\ \\( 2 (-2) - 7 ) - 3 (3 (-2) + 8) = 4 ( -2 ) + -9\\ \\ ( -4 - 7 ) - 3(-6 + 8 ) = - 8 - 9\\ \\ -11 - 3( 2 ) = -17\\ \\ -17 = -17\end{gathered}

(2z−7)−3(3z+8)=4z−9

(2z−7)−(9z+24)=4z−9

(2z−7)−9z−24=4z−9

2z−7−9z−24=4z−9

2z−9z−4z=−9+7+24

2z−9z−4z=−2+24

−11z=22

z=

11

22

z=−2

To check this

Putz=−2

(2(−2)−7)−3(3(−2)+8)=4(−2)+−9

(−4−7)−3(−6+8)=−8−9

−11−3(2)=−17

−17=−17

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