Question

2z²-12z-14=0. factorise method

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Answer 1

$2z {}^{2} - 12z - 14 = 0$

$z {}^{2} - 6z - 7 = 0$

$z {}^{2} - 7z + z - 7 = 0$

$z(z - 7) + 1(z - 7) = 0$

$(z - 7)(z + 1) = 0$

z =7 or z =-1

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Answer 2

Step-by-step explanation:

2z^2-12z-14=0

2z^2-14z+2z-14=0

2z(z-7)+2(z-7)=0

(2z+2)(z-7)=0

z=-2/2=-1 ,,,,,,z=7

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