Question

2z²+15z+30=0 find the nature of the following quadratic equations .if roots are excited find them.
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Answer 1

Answer:

2z^2 + 15z + 30 = 0

compare with ax^2 + bx + c = 0

a = 2 , b = 15 , c = 30

b^2 - 4ac = (15)^2 - 4 (2)(30)

= 225 - 240

b^2 - 4ac = -15

Since, b^2 - 4ac is less than 0 , the roots would be not real.

If you wanna find the exact roots, then please do substitute in the formula.

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Answer 2

Answer:

the ans is -15

explanation:-

comparing equation with az^2+bz+c = 0

a=2, b=15, c=30

b^2-4ac = (15)^2 - 4×2×30

= 225 - 240

∆ = - 15

hence, the root of this quadratic equation are not real.

Note:-

• when the value of b^2 - 4ac is positive means (greater than zero) than quadratic equation is real and unequal.
• when the value of b^2 - 4ac is equal to the zero than the quadratic equation is real and equal.
• when the value of b^2 - 4ac is negative means (smaller than the zero )than quadriatic equation are not real.

Hope this answer helpful to you ☺️✌️...