Question

2z²(z²+6z-16)÷(z²-4)​

Answer 1

Step-by-step explanation:

4yz(z

2

+6z−16)÷2y(z+8)

2y(z+8)

4yz(z

2

+8z−2z−16)

z+8

2z(z(z+8)−2(z+8))

⇒

(z+8)

2z[(z+8)(z−2)]

2z(z−2)=2z

2

−4z.

hope it helps you