Question

3
0.
30 .
3п.
M
n и am
6.02
with 61
512
|
3V, 0.24312
Find the current and current through 982. (S-18)​

Answer 1

Answer:

Loop AFMN : 20=5I1+12(II1−I2)

or 20=17I1−12I2 (i)

Loop AFBEA: 20+20=5I1+5I2 or 8=I1+I2 (ii)

Solving, we get I1=4A,I2=4A

So current through MNisI1−I2=4−4=0

And current through each of the battereis is 4A.

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