(3^0 + 4^-1) × 2^2
Please answer ASAP
Answers
Correct answer is 5.
As we know that,
As we know that,n
As we know that,n 0
As we know that,n 0 =1
As we know that,n 0 =1n
As we know that,n 0 =1n −1
As we know that,n 0 =1n −1 =
As we know that,n 0 =1n −1 = n
As we know that,n 0 =1n −1 = n1
As we know that,n 0 =1n −1 = n1
As we know that,n 0 =1n −1 = n1
As we know that,n 0 =1n −1 = n1 Therefore,
As we know that,n 0 =1n −1 = n1 Therefore,(3
As we know that,n 0 =1n −1 = n1 Therefore,(3 0
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=(
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4=
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45 ×4
As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45 ×4=5
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