Question

(3^0÷4^-1)×2^2 solve this question ​

Answer 1

Answer:

$1 \times 4 \times 4$

$16$

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\dfrac{ {3}^{0} }{ {4}^{ - 1} } \times {2}^{2} \\ \\ \dfrac{1}{ {4}^{ - 1} } \times 4 \\ \\ 4 \times 4 = 16$

Hope it helps u