Question

3√0.512/0.343÷ √0.64/0.49+1

Answer 1

that possible answer is 1

Answer 2

Answer:

2

Step-by-step explanation:

$\frac{ \sqrt[3]{0.512} }{0.343 } \div \frac{ \sqrt{0.6} }{0.49} + 1 \\ \frac{0.8}{0.7} \div \frac{0.8}{0.7} + 1 \\ \frac{0.8}{0.7 } \times \frac{0.7}{0.8} + 1 \\ 1 + 1 \\ = 2$

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