Question

-3 ,0 and 2 are the zeroes of the polynomial p (x ) = x cube + a-1 x square + bx + c then find a and c​

Answer 1

Answer:

a=14 , b= -30 ,c= 0

step by step explanation:

p(-3)=-3^3+3^2(a-1)+3b+c=0

(zero of polynomial)

= -27+9(a-1)+3b+c=0

= 9a+3b+c=36 ------------------------(i)

p(0)= 0^3+0^2(a-1)+0b+c=0

=c=0 -----------(ii)

p(2)=2^3+2^2(a-1)+2b+c=0

= 8+4(a-1)+2b+c=0

= 4a+2b+c=-4 -----------------(iii)

from (i),(ii)&(iii)

3a+b=12

2a+b=-2

subtracting eqns

3a-2a=12+2

a=14

& b= -30

& c= 0