Question

3.0 g of H2 react with 29.0 9 3 points
of O2 to yield H20. calculate
the maximum amount of H2O
that can be formed. *
O 2.50 mol
O
1.0 mol
1.50 mo
ОО
O 0.150 mol​

Answer 1

Answer:

2H2 + O2 = 2H2O

Incase of Hydrogen, 4*1= 4g

                oxygen = 2*16 = 32g

               water = 2(2+16) = 36 g

so 4g of H2 needs 32 g of oxygen to form water

Here, 3g of H2 reacts with 29 g of oxygen

4g of H2 forms 36g of water

3g of H2 forms $\frac{3 * 36}{4}$

Hence amount of water formed = 27g

one molecule of water = 18 g

so 27 g = 18g + 9g

             = one molecule + half molecule

              = 1.5 molecules of water is formed