Question

3.0 g of H2 react with 29.0 g of O2 to form H20 according to chemical equation 2H2 + O2 = 2H2O.
A) which is the limiting reactant?
B) calculate the maximum amount of H2O that can be formed?
C) calculate the amount of reactants left unreacted

Answer 1

Answer:

here is your answer hope it help you

Answer 2

Answer:

A ) Hydrogen is the limiting agent

B )1.49 moles H₂O ( 26.82 g )

C ) 0.161 mole of O₂ ( 5.15 g )

Explanation:

3.0 g of H₂ = 1.49 moles of H₂

29.0 g of O₂ = 0.906 moles of O₂

A ) 0.906 mole of O₂ requires 1.81 moles of H₂.

     so, hydrogen is the limiting agent.

B ) 1.49 moles of H₂ reacts with 0.745 mole of O₂ and gives 1.49 moles of H₂O

C ) The reactant left behind is the oxygen.

    0.161 mole ( 0.906 - 0.745 ) of O₂ is left unreacted.