3.0 molal sodium hydroxide (naoh) solution has a density of 1.110g/ml. the molarity of this solution is
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It is given that the density of the solution is 1.110 g mL
−1
.
The concentration of sodium hydroxide solution is 3.0 molal.
This implies 1000 g of water has 3 moles of NaOH.
3 moles of NaOH =3×40=120 g of NaOH
Mass of solution =1000+120=1120 g
Volume of solution =
Density
Mass
=
1.11
1120
=1009 mL
Molarity =
Volume in L
Number of moles
=
1000
1009
3
=2.97 M
Hence, the molarity of the solution is 2.97 M.
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