3.00 moles of ideal gas is heated at constant pressure from 27°C to 127°C
Calculate the work of expansion
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Answers
Answered by
8
a.
T initial = 27 0C =300K
T final = 127 0C = 400K
V initial = nRTinitial /P
V final = nRT final /P
W= -PV=- p(V final – V initial ) = -(P nR/p)*( T final – T initial )
= - 3 x 8.314 x ( 400-300)=-2494.2 J
Answered by
3
Answer:
change in temp. = 100 degree celsius
moles= 3.00
therefor expansion = 3*100
= 300
Explanation:
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