Question

3×01×10^22 molecules of N2 then, mass/volume of compound of N2 at STP​

Answer 1

Answer:

The volume occupied by the 1mole of N

2

=22.4l

So, the 1mole=6.022×10

23

molecules of N

2

=

6.022×10

23

22.4

So, 6.022×10

22

molecules of N

2

would occupy volume

=

6.022×10

23

l

22.4

×6.022×10

22

=2.24l

Thus ,the right option is B