Question

3.01×10^24 molecules of sucrose are present in 10L of its solution. the molarity of the solution is​

Answer 1

Answer:

Explanation: this question is solved on the formula of MOLE = molarity × volume

GIVEN  :-

Number of molecule  = 3.01 ×10^24

volume = 10L

now,

     MOLE =   NO. OF MOLECULES / 6.022 ×10^23

                = 3.01 × 10^24   /  6.022 × 10^23

                 = 5 MOLE

    NOW

              n(mole)  =  M (molarity) ×  v(volume)

               5         =     M        ×     10

                M    =   5 / 10

 THAT IS  M =  0.5

SO THE ANSWER IS 0.5 M.                      

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Answer 2

Given - Number of molecules - 3.01×10²⁴

Volume - 10 litre

Find - Molarity of solution

Solution - We know 1 mole of any compound contains number of molecules equal to Avogadro's number.

Number of moles of 6.022 × 102²³ molecules = 1

Number of moles of 3.01×10²⁴ molecules = 3.01×10²⁴/6.022 × 102²³

Number of moles = 4.99

Number of moles = 5

Now, formula of molarity is = number of moles/volume of solution in litres

Molarity = 5/10

Molarity = 0.5

Hence, molarity of solution is 0.5