Question

3.011×10^23 of ammonia gas molecules find volume at stp

Answer 1

Answer: The volume of ammonia gas will be 11.2 L.

Explanation:

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

We are given:

Number of ammonia gas molecules = $3.011\times 10^{23}$

So, number of moles of these number of molecules will be = $\frac{3.011\times 10^{23}}{6.022\times 10^{23}}=0.5moles$

At STP:

1 mole of a gas occupies 22.4 L of volume.

So, 0.5 moles of a gas will occupy = $\frac{22.4}{1}\times 0.5=11.2L$

Hence, the volume of ammonia gas will be 11.2 L.