Question

-3,0and 2are the zeros of the polynomial p(x)=x^3+(a-1)x^2+bx+ c find a and c.​

Answer 1

Step-by-step explanation:

p(-3)=0

p(-3)=0^3+(a-1)0^2+b(0)+c

p(-3)=c

so,

c=0

p(2)=0

p(2)=2^3+(a-1)2^2+b(2)+c

p(2)=8+4(a-1)+2b+0

p(2)=8+4a-4+2b

p(2)=4a+2b+4

so,

4a+2b+4=0

2a+b+2=0

2a=-(b+2)

a= -(b+2)/2