Question

(3¬ – 1)
1. 1+3 + 32 + ... + 3n-1 =
​

Answer 1

Answer:

sum_(k=3 k)^n 3 k = -3/2 (3 k - n - 1) (3 k + n)

Step-by-step explanation:

Answer 2

I didn't get ur question

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