Question

(√3+1) (√1+-2)+9/√3+√12​

Answer 1

$\textbf{\underline{\pink{\underline{\large{Step by step Explanation:-}}}}}$

$( \sqrt{3} + 1)( \sqrt{1} + ( - 2)) + \frac{9}{ \sqrt{3} } + \sqrt{12} \\ = ( \sqrt{3} + 1)(1 - 2) + \frac{9}{ \sqrt{3} } + 2 \sqrt{3} \\ = ( \sqrt{3} + 1)( - 1) + \frac{9 + 6}{ \sqrt{3} } \\ = - \sqrt{3} - 1 + \frac{15}{ \sqrt{3} } \\ = \frac{ - 3 - \sqrt{3} + 15}{ \sqrt{3} } \\ = \frac{12 - \sqrt{3} }{ \sqrt{3} } \\ = \frac{12 - \sqrt{3} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ = \frac{ \sqrt{3}(12 - \sqrt{3} ) }{3} \\ = \frac{12 \sqrt{3} - 3 }{3}$

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Answer 2

Answer:

Step-by-step explanation: