Question

(-3)-1=1/(-3)^1 slove​

Answer 1

Answer:

How do you solve 3 1/3 - 2 1/5 =?

n=313−215

⟹n=(3−2)+(13−15)

⟹15n=15(1+13−15)

⟹n=15+5−315

⟹n=1515+215

n=1215

n=313−215

⟹n=93+13−105−15

⟹15n=15(103−115)

⟹n=50−3315

⟹n=1715

⟹1515+215

n=1215

313−215=103−115=50−3315=1715=1215

First, you have to change them to improper fraction. Then, you need to have the same denominator for both of the fractions.

Solution:

3 1/3 = 10/3

2 1/5 = 11/5

So, the common denominator would be 15 (3 ×5).

10/3 = 50/15

(15 ÷ 3 = 5 × 10 = 50)

11/5 = 33/15

(15 ÷ 5 = 3 × 11= 33)

Next,

ANSWER: 50/15 - 33/15 = 17/15 or (1 2/15)

Answer 2

Given,

$\[{\left( { - 3} \right)^{ - 1}} = \frac{1}{{{{\left( { - 3} \right)}^1}}}\]$

Solution,

Consider the left hand side of the problem,

$\[\begin{array}{l} = {\left( { - 3} \right)^{ - 1}}\\ = \frac{1}{{{{\left( { - 3} \right)}^1}}}\end{array}\]$

This is equal to right hand side of the expression.

Hence the given condition is proved.