Question

[3{1^1/3+8^1/3}^2]^2/3

Answer 1

[3 $(1^{1/3} +8^{1/3})^{2}$ ]$^{2/3}$

cube root of 1 is 1

cube root of 8 is 2

so

[ 3 $(1 +2)^{2}$]$^{2/3}$

[ $3^{3}$ ]$^{2/3}$

= $3^{2}$

9

brainliest please