Question

3^1/2 and -3^1/2 are the zeroes of f(x)= x^4 -3x^3 -x^2 +9x -6

Answer 1

Answer:

Given that,

√3 and -√3 are the zeros of x⁴-3x³-x²+9x-6

For finding other zeros

x =√3

=> (x-√3)

x = -√3

=> (x+√3)

Multiple both of the zeros

(x-√3) (x+√3) = x²-3

x⁴-3x³-x²+9x-6 ÷ x²-3 = x²-3x+2

=> x²-3x+2

=> (x-1)(x-2)

=> x = 1, 2

Hope it helps you ❤️

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