- 3, 1
- 3, - 1
3, - 1
3, 1
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Answer:
C .
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Answered by
1
x²-2x-3
=x²+x-3x-3
=x(x+1)-3(x-1)
=(x-3)(x-1)
x=1,3
Therefore 1 and 3 are zeroes of the given polynomial
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