Math, asked by gacSDAShogacho, 8 months ago

- 3, 1
- 3, - 1
3, - 1
3, 1

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Answers

Answered by Anonymous
0

Answer:

C .

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Answered by suhrutha21
1

x²-2x-3

=x²+x-3x-3

=x(x+1)-3(x-1)

=(x-3)(x-1)

x=1,3

Therefore 1 and 3 are zeroes of the given polynomial

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