√3-1/√3+1. A-b√3. Find a and b values
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Question must be :
If (√3 - 1)/(√3 + 1) = a - b√3, find a and b
Solution :
Now,
(√3 - 1)/(√3 + 1)
= (√3 - 1)/(√3 + 1) * (√3 - 1)/(√3 - 1),
by multiplying both the numerator and the denomination by the conjugate irrational number of its denominator
= {(√3 - 1)(√3 - 1)}/{(√3 + 1)(√3 - 1)}
= (3 - √3 - √3 + 1)/(3 - √3 + √3 - 1)
= (4 - 2√3)/(2)
= 2 - √3
Given that,
2 - √3 = a - b√3
Comparing both sides, we get
a = 2 and b = 1
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