√3-1\√3+1 = a-b√3. find the value of a and b.
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Answer:
a=2 and b=1
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vickygupta37:
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(√3 - 1)/(√3 + 1) = a - b√3
On rationalizing the LHS...
=> [(√3 - 1)/(√3 + 1)]×[(√3 - 1)/(√3 - 1)]
=> [(√3)² + (1)² - 2×√3×1]/ (√3)² - (1)²
=> (3 + 1 - 2√3)/ (3 - 1)
=> (4 - 2√3)/2
=> 2(2 - √3)/2
=> 2 - √3 = a - b√3
On comparing both sides we get,
a = 2 and b = 1
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